Question

A particle moves towards East with velocity 5m/s.After 10 seconds its direction changes towards north with same velocity .The average acceleration of the particle is
(a)Zero
(b)1/√2m/s^2N-W
(c)1/√2m/s^2N-E
(d)1/√2m/s^2S-W
(d)1/√2m/s^2S-W
​

Answer 1

Answer:

option B

Step-by-step explanation:

Intial velocity=v1=5m/seast wards

then after time t=10sec

v2=5m/s north wards

δv=

V

1

2

+

V

2

2

=

25

+25

=5

2

acceleration a=

time

velocity

=

10

5

2

=

2

2

×

2

2

=

2

1

towards n-w

Answer 2

Answer:

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