Question

A particle moves under an attractive force F=-K/r2in a circle of radius r the total energy of revolving particle is​

Answer 1

answer : -K/2r

explanation : given, a particle moves under an attractive force, F = - K/r² in a circle of radius r.

so, To move particle in circular motion, a centripetal force is acting to balance the attractive force.

i.e., centripetal force = attraction force

or, mv²/r = K/r²

or, mv² = K/r

so, kinetic energy of particle , K.E = 1/2 mv² = 1/2 (K/r) = K/2r

again, potential energy , U = - negative of workdone

= - F.dr

= -∫(-K/r²).dr

= K ∫dr/r²

= K [-1/r]

= -K/r

so, total force = K.E + U

= K/2r - K/r

= -K/2r

hence, total energy of revolving particle is -K/2r

Answer 2

Answer:

Explanatnow u can get an easy way to solve this