Question

what is the potential drop between the points A and C in the following circuit
resistances 1 and 2 ohms are the internal Resistances of respective cells​

Answer 1

Answer:

1.25 V

Explanation:

Current = V/R = (2+4)/(1+2+5) = 0.75 A

Potential difference in a cell = V - Ir (r = internal resistance) - you can prove it by kirchoff rule

Ans = 2 - 0.75x1 = 1.25 V

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