Question

. A particle moves under the action of a force F = 20 i + 15 j along a straight line 3y + ax = ,
where, a is a constant. If the work done by the force F is zero, then the value of a is​

Answer 1

Answer:

Explanation:

F = 20i + 15j

3y + ax

Work done =0

Since workdone is dot product

20×a + 15×3= 0

20a = -75

a = -75/20

= -15/4