Question

A particle moves
under the influence
by F-3X² - 2x +7
The work done by
from x=0 to x=5m,
of a force F(in N given
this
force
is​

Answer 1

Answer:

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Answer 2

Answer:

$\sf \displaystyle 135 \ J$

Explanation:

Given :

$\sf F=3x^2-2x+7$

$\sf Distance \ moved=0 \ to \ 5$

We are asked to find Work done :

We know :

$\sf \displaystyle W=\int\limits^{x_2}_{x_1} {F} \, dx$

$\sf \displaystyle W=\int\limits^{5}_{0} {(3x^2-2x+7)} \, dx$

$\sf \displaystyle W=\left|\dfrac{3x^3}{3} -\frac{2x^2}{2}+7x \right|^{5}_{0}$

$\sf \displaystyle W=\left|x^3-x^2+7x \right|^5_0$

Putting limits vales :

$\sf \displaystyle W=\left(5^3-5^2+7.5 \right) -(0^3-0^2+7.0)$

# Here dot ( . ) means 'multiply by' or 'times' :

$\sf \displaystyle W=\left(125-25+35 \right ) \ J$

$\sf \displaystyle W=135 \ J$

Hence we get required answer.