Question

A particle moves with the constant velocity of 25 metre per second what is acceleration in the body answer

Answer 1

Explanation:

Answers

See the diagram enclosed.

At t=0, start at O, origin. Draw a line to A with a slope of 5 for 5 seconds. For every one second move up by 5 units vertically.

Then draw a horizontal line for 4 seconds reaching D. here t= 9sec.

Now join D with E at t= 9+5 = 14sec on

time sline when the body stops ie., velocity is 0. The slope here is found by height lost / horizontal span = 25/5 = 5 m/sec²

a) V at A: 25 m/sec

b) Area enclosed by triangle OAB = 1/2* 25 * 5 = 62.5 m

c) area of ABCD = 25 * 4 = 100 m d) slope = (0-25)/5 = -5 m/sec² -

e) area of triangle DCE = 62.5 m

f) total area bounded between the OADE and time axis. = 62.5 +100 + 62.5 = 230m