A particle moves with uniform acceleration along
straight line AB.Its velocities at A and B are 2m/s
and 14 m/s respectively. M is the mid point of AB.If
the particle takes 2 seconds to go from A to M,
then time taken to travel from M to B is
(1) 1s
(2) 2s
(3) 3
(4) 45
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Answer:
Explanation:
=> Here, A particle moves with uniform acceleration along straight line AB.Its velocities at A and B are 2m/s and 14 m/s respectively. M is the mid point of AB.
v²=u²+2as
v² = 2² + 2as
v² - 4 = 2as ...(1)
14² = v² + 2as
196 - v² = 2as ...(2)
From eq (1) and (2), we get
196 - v² = v² - 4
2v² = 200
v² = 100
v = 10 m/s.
=> time taken to travel from A to M
v = u + at1
t1 = v - 2 / a
= 10 - 2 / a
= 8 / a
=> time taken to travel from M to B
t2 = 14 - v / a
14 - 10 / a
= 4 / a
=> t2 / t1 = 4/a / 8/a = 1 / 2 a
Thus, time taken to travel from M to B is 1s.
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