Question

A particle moving along circular path of radius 1m completes 2(1/4)th revolution. Then displacement and distance of the particle are

Answer 1

Answer:

given =  moving particle in circular path

              radius = 1m

              revolution = 2(1/4th)

to find = displacement and distance of particle

solution =

for distance AC = $\sqrt{1^{2}+ 1^{2} }$

                    AC = √2

total distance covered by the particle is

        2πr + 2πr + 2πr / 4(circumference of a circle using the radius)

        4πr + πr/2

        4π + π/2

        9π/2

displacement and distance of the particle are √2 & 9π/2 respectivily.

Answer 2

Answer:

1 : 1

B

0 : 1

C

π:1

D

π:2

Easy

Answer

Distance=π∗R=π displacement=2∗R=1∗2=2

therefore the ratio the distance covered and the displacement in half revolutionr=

2

π