Question

A particle moving along positive x-axis changes its position from x = 5 m to x = 10 m in time 2 s. The magnitude of average velocity of particle is​

Answer 1

Answer:

A particle moving along positive x-axis changes its position from x = 5 m to x = 10 m in time 2 s. The magnitude of average velocity of particle is (1) 2.5 m/s (2) 2 m/s (3) 3.5 m/s (4) 3 m/s.

Answer 2

The magnitude of average velocity of particle is​  $\frac{5}{2}$ m$s^{-1}$.

Explanation:

• We know that velocity is measured by calculating distance travelled by a certain object per unit time. Now, when we bring the concept of average velocity, we indicate the change in the positions of displacements of a certain object and the change in time when the displacement was performed by the object.

Average velocity is the measure of change in the displacement of the object divided by the change in the time.

• Now, According to the given information, a particle moving along positive x-axis changes its position from x = 5 m to x = 10 m in time 2 s.  This means that the displacement of the particle changes from 5 m. on the x axis to 10 m. on the x axis. This means that the change in the displacement is equal to = 10 - 5  = 5 m.

Also, the time given here is 2 s, which means that the particle change its positions of displacement within a time period of 2 s.

Then, average velocity is equal to  $\frac{5}{2}$ m$s^{-1}$.

Hence, the magnitude of average velocity of particle is​  $\frac{5}{2}$ m$s^{-1}$.

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