Question

A particle moving along with an initial velocity of 5m/s is subjected to a uniform accelaration of 2.5m/s square. Find displacement in next 4 sec

Answer 1

here is your answer

given :

initial velocity = 5 m/s

acceleration = 2.5 m/s²

time = 4 seconds

to find : displacement

solution :

by using 2nd equation of motion

s = ut+1/2at²

s = 5*4+1/2*2.5*(4)²

s = 20+20

s = 40 meter

so, displacement is 40 meter.

Answer 2

$\huge\underline\pink{\tt Hey \: mate }$

Answer:

initial velocity = 5m/s

acceleration = 2.5m/s²

time = 4 second

Distance = ?

S = 5 × 4 + 1/2 × 2.5 × 16

S = 20 + 20

Hence distance travelled is 40m

$\huge\underline\blue{\tt Thank \: u }$