A particle moving along x-axis has, at any instant, its coordinate to be x=4+3t+5t^2. What is the value of dx/dt at t=1?
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Answered by
5
Answer:
x=4+3t+5t^2
dx/dt= d/dx (4)+d/dx(3t)+d/dx(5t^2)
= 0+3+10t
=10t+3
When t=1
10(1)+3 =13
Answer: 13
Answered by
0
Answer:
13 is the correct answer
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