The coordinates of one end of point of a diameter a b of a circle at 3, 4 in the coordinates of centre at - 1, 0 find the coordinates of the other end of the diameter
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.___1__.____1_.
A. B. C
(x,y). (-1,0). (3,4)
Coordinates of B =(x1+x2)/2. ,. (Y1+y2)/2
-1=x+3/2
x=-5
0=y+4/2
y=-2
So A (other end of diameter) is (-5,-2)
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