Question

a particle moving in a straight line covers half the distance with speed of 3m/s . the other half is coverd in two equal time intervals with speed of 4.5m/s ansd 7.5m/s respectively the average speed of the particle during the motion is ​

Answer 1

Explanation:

Suppose total distance is 2x

then first half is 2x traveled with 3m/s so time taken t

1

=

3

2x

after it suppose it take 2t time then

its half i.e. t with 4.5m/s so distance s

1

=4.5t

another half i.e. t with 7.5m/s so distance s

2

=7.5t

this distance s

1

+s

2

=2x or 4.5t+7.5t=12t=2x or x=6t

Average speed is v=

time

distance

=

t

1

+2t

4x

=

3

2x

+2t

4x

putting x=6t we get v=4m/s