Question

A particle moving in a straight line, starts from rest with a constant acceleration 2 m/s2. Displacement of particle in 5 seconds is:​

Answer 1

Step-by-step explanation:

let displacement = s

u =0m/s

a= 2m/s^2

t=5 sec

s= ut+1/2at^2

s=0×5 + 1/2×2×5×5

s= 0+ 25

s=25 meter

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Displacement=25\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Acceleration(a) = 2 \: m/{s}^{2} \\ \\ \tt: \implies Time(t) = 5 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Displacement(s) =?$

• According to given question :

$\tt \circ \:Initial \: velocity = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2}a {t}^{2} \\ \\ \tt: \implies s = 0 \times 5 + \frac{1}{2} \times 2\times {5}^{2} \\ \\ \tt: \implies s =0 + 25 \\ \\ \green{\tt: \implies s =25 \: m} \\ \\ \green{\tt \therefore Displacement \: of \: particle \: is \: 25 \: m} \\ \\ \blue{ \boxed{\bold{Some \: related \: formula}}} \\ \\ \orange{ \tt \circ \: v = u + at} \\ \\ \orange{ \tt \circ \: {v}^{2} = {u}^{2} +2as}$