a particle moving in one 1d with constant acceleration of10 m per second is observed to cover a distance of 100m during a 4s interval how far will the movie in next 4s
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acceleration (a)=10m/s^2
displacement(d)=100m
time taken (t)=4s
initial velocity (u)=d/t=100/4=25m/s
we know that,
a=v-u/t[where,v=final velocity]
10=v-25/4
v=65m/s
now,
v=d/t[for next time=4s]
65=d/4
d=260m/s
so distance travelled in next four second
=260-100=160m/s
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