Question

A particle moving in one- dimension with constant acceleration of 10m/s^2 is observed to cover a distance of 100 m during a 4s interval. How far will the particle move in the next 4s?

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Answer 1

here ,
a = 10 m/s² { acceleration }
u = ?{ initial velocity)
t = 4 sec ,

use kinematics equation,
S = ut + 1/2at²
100 = u× 4 + 1/2 × 10 × 16
100 - 80 = 4u
u = 5 m/s

again,
use formula,
v² = u² + 2as
v² = (5)² + 2 × 10 × 100
= 2025
v = √(2025) = 45 m/s

now, v = 45 m/sec is the initial velocity for next 4sec , and acceleration is 10m/s²
S = ut + 1/2 at²
= 45 × 4 + 1/2 × 10 × 16
= 180 + 80
= 240 m

Answer 2

Answer:

Explanation:

Here ,

a = 10 m/s² { acceleration }

u = ?{ initial velocity)

t = 4 sec ,

use kinematics equation,

S = ut + 1/2at²

100 = u× 4 + 1/2 × 10 × 16

100 - 80 = 4u

u = 5 m/s

again,

use formula,

v² = u² + 2as

v² = (5)² + 2 × 10 × 100

= 2025

v = √(2025) = 45 m/s

now, v = 45 m/sec is the initial velocity for next 4sec , and acceleration is 10m/s²

S = ut + 1/2 at²

= 45 × 4 + 1/2 × 10 × 16

= 180 + 80

= 260

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