Show that only one of the numbers (n+2), n and (n+4) is divisible by 3 where n is any positive integer
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first consider n be 1
n+2=3
n=1
n+4=5
second consider n be 2
n+2=4
n=2
n+4=6
third consider n be 3
n+2=5
n=3
n+4=7
as we can see that only one no. is divisible by 3 in each and the process will continue in the same manner as we are seeing only the no. to be divided we can say that in n+2,n,n+4 only one no. is divisible by 3 at a time
n+2=3
n=1
n+4=5
second consider n be 2
n+2=4
n=2
n+4=6
third consider n be 3
n+2=5
n=3
n+4=7
as we can see that only one no. is divisible by 3 in each and the process will continue in the same manner as we are seeing only the no. to be divided we can say that in n+2,n,n+4 only one no. is divisible by 3 at a time
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