Question

A particle moving in the xy plane undergoes a displacement of $\vec{s}=(2\hat{i}+3\hat{j})$ while a constant force $\vec{F}=(5\hat{i}+2\hat{j})$ N acts on the particle. The work done by the force F is(a) 17 joule (b) 18 joule(c) 16 joule (d) 15 joule

Answer 1

sry I don't know the ans

Answer 2

Answer:

C 16Joule

Explanation:

W=F*s

Work Done= 2*5 + 3*2

=16 Joules