Question

A particle moving on a square track of side 5m from one corner with constant velocity of 10m/s. then in 5sec magnitude of it's average velocity is

Answer 1

• time taken to cover 1 side: 0.5sec
• particle comes back to its initial position after 2sec
• after 5 sec particle is diagonally opposite to the starting point.
• avg velocity= 5√2/5= 1.4 m/sec