Question

A particle moving with 20cm/s collides normally with a wall and rebounds with 10cm/s. If the collision happens within 0.2 s and if the mass of the partical is 100 g what is the force exerted on the wall ?
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Answer 1

Answer:

the answer is 0.05N

hope it helps u

Answer 2

The force exerted on the wall is 0.15 N

Explanation:

Let the force exerted by the wall is F

Impulse by the wall = F × t

Where t = 0.2 s

Mass of the particle = 100 g = 0.1 kg

Initial velocity u = 20 cm/s

velocity after impact v = -10 cm/s

We know that

Impulse = Change in momentum

$F\times t=mu-mv$

$\implies F\times 0.2 = 0.1(20+10)\times 10^{-2}$

$\implies F\times 0.2 = 3\times 10^{-2}$

$\implies F=\frac{3\times 10^{-2}}{0.2}$ N

$\implies F=0.15$ N

Hope this answer is helpful.

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