Question

a particle moving with an initial velocity of 5m/s in subjected to a uniform acceleration of-2.5m/s square .find the displacement in next 4 sec

Answer 1

USING 2ND EQUATION OF MOTION
i.e.
s {displacement} = u{initial velocity} t + 1/2 a {t square}

Here we will take acceleration as +2.5 m/s square because its rectilinear motion i.e. motion in one dimension

s = ut + 1/2 a ( t square )
s = 5 × 4 + 1/2 × ( 2.5 ) × 4 × 4
s = 20 + ( 2.5) × 2 × 4
s = 20 + ( 20 )
s = 40 m
ANSWER = 40m

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Answer 2

Answer:

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