the boat goes 30 kilometre upstream and 44 km downstream in 10 hours in 13 hours it can go 40 kilometre upstream and 55 km downstream determine the speed of stream of and the of the boat in still water
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Answered by
15
Let speed of the boat be x km/h
speed of the stream be y km/h
then the speed of boat downstream =(x+y)km/h
the speed of boat upstream =(x-y)km/h
30/x-y +44/x+ y =10 _________eq 1
40/ x-y + 55/ x+y =13 _____________eq 2
put 1/ x-y=u and 1/x+ y =v
30u + 44v = 10
40u +55 v=13
using cross multiplcitation
methods
u/44 (- 13 )- 55( - 10) = v/40( - 10) - 30 (- 13) = 1 / 30 (55 )- 44(40)
u/- 22 =4 /- 10 =1/ -110
u = 1 / 5 v= 1 /11
now put this value of U and V in equation 3 we get
1/x-y =1/5 and 1/x+y= 1/11
x-y=5and x+y=11
adding this equation we get
2x = 16
x = 8
subtracting the equation in 6 we get
2 Y = 6
Y = 3
speed of the stream be y km/h
then the speed of boat downstream =(x+y)km/h
the speed of boat upstream =(x-y)km/h
30/x-y +44/x+ y =10 _________eq 1
40/ x-y + 55/ x+y =13 _____________eq 2
put 1/ x-y=u and 1/x+ y =v
30u + 44v = 10
40u +55 v=13
using cross multiplcitation
methods
u/44 (- 13 )- 55( - 10) = v/40( - 10) - 30 (- 13) = 1 / 30 (55 )- 44(40)
u/- 22 =4 /- 10 =1/ -110
u = 1 / 5 v= 1 /11
now put this value of U and V in equation 3 we get
1/x-y =1/5 and 1/x+y= 1/11
x-y=5and x+y=11
adding this equation we get
2x = 16
x = 8
subtracting the equation in 6 we get
2 Y = 6
Y = 3
Answered by
15
Hello !
Speed of boat = x km/hr
Speed of stream = y km/hr
While going upstream ,
speed = (x - y) km/hr
distance = 30 km
time = distance / speed = 30 / x-y hours
While going downstream ,
speed = (x + y) km/hr
distance = 44 km
time = distance / speed = 44 /x + y hours
Total time = 10 hr
30 / x-y + 44 /x + y = 10
Let ,
1/x -y = u , 1/x+y = v
the equation becomes :-
30u + 44v = 10 -----> [1]
----------------------------------
While going upstream ,
speed = (x - y) km/hr
distance = 40 km
time = distance / speed = 40 / x-y hours
While going downstream ,
speed = (x + y) km/hr
distance = 55 km
time = distance / speed = 55 /x + y hours
Total time = 13 hrs
40 / x-y + 55 /x + y = 13
Let ,
1/x -y = u , 1/x+y = v
the equation becomes :-
40u + 55v = 13 ----> [2]
-----------------------------------------
solving equations 1 and 2 ,
3 x (40u + 55v = 13 )
4 x (30u + 44v = 10)
120 u + 165v = 39 ----> [3]
120u + 176v = 40 ----> [4]
Subtracting equation 3 from 4 , we get ,
11v = 1
v = 1/11
also ,
40u + 55v = 13
40u + 55 x 1/11 = 13
40u + 5 = 13
40u = 13 -5
40u = 8
u = 8/40 = 1/5
given ,
1/x -y = u
1/x -y = 1/5
cross multiplication ,
x -y = 5
similarly,
1/x+y = v
x +y = 11
solving ,
x +y = 11
+ x - y = 5
--------------
2x = 16
x = 8
x -y = 5
8 -y = 5
y = 3
==============================
x = 8 , y = 3
Speed of boat = 8 km/hr
speed of current = 3 km/hr
Speed of boat = x km/hr
Speed of stream = y km/hr
While going upstream ,
speed = (x - y) km/hr
distance = 30 km
time = distance / speed = 30 / x-y hours
While going downstream ,
speed = (x + y) km/hr
distance = 44 km
time = distance / speed = 44 /x + y hours
Total time = 10 hr
30 / x-y + 44 /x + y = 10
Let ,
1/x -y = u , 1/x+y = v
the equation becomes :-
30u + 44v = 10 -----> [1]
----------------------------------
While going upstream ,
speed = (x - y) km/hr
distance = 40 km
time = distance / speed = 40 / x-y hours
While going downstream ,
speed = (x + y) km/hr
distance = 55 km
time = distance / speed = 55 /x + y hours
Total time = 13 hrs
40 / x-y + 55 /x + y = 13
Let ,
1/x -y = u , 1/x+y = v
the equation becomes :-
40u + 55v = 13 ----> [2]
-----------------------------------------
solving equations 1 and 2 ,
3 x (40u + 55v = 13 )
4 x (30u + 44v = 10)
120 u + 165v = 39 ----> [3]
120u + 176v = 40 ----> [4]
Subtracting equation 3 from 4 , we get ,
11v = 1
v = 1/11
also ,
40u + 55v = 13
40u + 55 x 1/11 = 13
40u + 5 = 13
40u = 13 -5
40u = 8
u = 8/40 = 1/5
given ,
1/x -y = u
1/x -y = 1/5
cross multiplication ,
x -y = 5
similarly,
1/x+y = v
x +y = 11
solving ,
x +y = 11
+ x - y = 5
--------------
2x = 16
x = 8
x -y = 5
8 -y = 5
y = 3
==============================
x = 8 , y = 3
Speed of boat = 8 km/hr
speed of current = 3 km/hr
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