a particle moving with an initial velocity of 5m/s is subjected to a uniform acceleration of 2.5m/s^2 . find the displacement in the next 4 SEC.
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U can use newton's 2nd equation of motion ans get the result as 40 m
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Answered by
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U is 5
A is 2.5
T is 4
S = ut+½at²
S = 5×4+½×2.5(4)²
S = 20 + 20
S = 40
Here we can take displacement as distance that's why here I took displacement as s
A is 2.5
T is 4
S = ut+½at²
S = 5×4+½×2.5(4)²
S = 20 + 20
S = 40
Here we can take displacement as distance that's why here I took displacement as s
very thxx
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