A particle moving with constant acceleration covers a distance of 30m in 3rd sec and a distance of 50m in 5th sec what is the initial velocity
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Answer:
The Initial velocity is 1
Explanation:
A particle moving with constant acceleration covers a distance of 30m in 3rd sec and a distance of 50m in 5th sec what is the initial velocity
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Given : A particle moving with constant acceleration covers a distance of 30 m in 3rd second and it covers a distance of 50 m in 5th second.
To find : The acceleration of particle.
solution : let initial velocity is u and constant acceleration is a.
distance covered in nth second is given by,
case 1 : S₃ = 30m , n = 3
so, 30 = u + 1/2 a(2 × 3 - 1)
⇒30 = u + 2.5a ............(1)
case 2 : S₅ = 50m , n = 5
so, 50 = u + 1/2 a (2 × 5 - 1)
⇒50 = u + 4.5 a ...........(2)
from equations (1) and (2) we get,
50 - 30 = [u + 4.5a ] - [u + 2.5a ]
⇒20 = 2a
⇒a = 10 m/s²
Therefore the acceleration of particle is 10 m/s²
hope its helps
To find : The acceleration of particle.
solution : let initial velocity is u and constant acceleration is a.
distance covered in nth second is given by,
case 1 : S₃ = 30m , n = 3
so, 30 = u + 1/2 a(2 × 3 - 1)
⇒30 = u + 2.5a ............(1)
case 2 : S₅ = 50m , n = 5
so, 50 = u + 1/2 a (2 × 5 - 1)
⇒50 = u + 4.5 a ...........(2)
from equations (1) and (2) we get,
50 - 30 = [u + 4.5a ] - [u + 2.5a ]
⇒20 = 2a
⇒a = 10 m/s²
Therefore the acceleration of particle is 10 m/s²
hope its helps
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