Question

A particle moving with intial velocity of 5 m/s is subjected to a uniform acceleration of 2.5m/s find displacement in next 4 sec

Answer 1

Answer:

40 metres

Explanation:

Given :

• Initial velocity = u = 5 m/s

• Acceleration of the particle = a = 2.5 m/s²

• Time the particle was accelerated for = t = 4 seconds

To find :

• Displacement of the particle after 4 seconds

Using the second equation of motion :

S=ut+½×at²

S=5×4+½×2.5×16

S=20+20

S=40 metres

The Displacement of the particle after 4 seconds is equal to 40 metres

Answer 2

Answer:

Given:

• A particle moving with initial velocity of 5 m/s is subjected to a uniform acceleration of 2.5m/s.

Find:

• Find displacement in next 4 second.

Know terms:

1. Initial velocity = (u)
2. Acceleration = (a)
3. Time taken = (t)
4. Displacement = (s)

Know terms:

☆ ${\sf{\underline{\boxed{\orange{\sf{s = \dfrac{ut + at^2}{2} }}}}}}$

Calculations:

⇒ $\bold{s = 5 \times 4 + 2.5 \times \dfrac{4^2}{2}}$

⇒ $\bold{s = 20 + 20}$

⇒ ${\sf{\underline{\boxed{\red{\sf{s = 40 \: m }}}}}}$

Therefore, 40 m is the displacement in next 4 second.