Physics, asked by abhaykumar10745, 8 months ago

A particle moving with speed 20 m/s
comes to rest in. 50s, find
A. Accelaration
B. Distance covered.​

Answers

Answered by cutepie223
1

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Answered by Anonymous
1

Answer:

v = 0m/s

u = 20m/s

t = 50s

a = ?

[ a = v - u / t ]

a = 0m/s - 20m/s / 50s

a = -20m/s / 50s

a = -0.4m/s^2

acceleration = -0.4m/s^2

u = 20m/s

t = 50s

a = -0.4m/s^2

s = ?

[ s = ut + 1/2at^2 ]

s = 20m/s * 50s + 1/2 * -0.4m/s^2 * ( 50s )^2

s = 1000m + ( -0.2m/s^2 ) * 2500s^2

s = 1000m - 500m

s = 500m

distance = 500m

༄ hope it helps ༄❆

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