Math, asked by arunbalan9241, 10 months ago

Let R be the region in the first quadrant bounded by the x-axis, the graph of x=y2+2, and the line x=4. What is a the interval for the area of R?


Anonymous: ___k off

Answers

Answered by piyushy002
0

Answer:

x

goes from  

2

to  

4

and  

y

goes from  

0

to  

2

.

Explanation:

Sketch the graph of  

x

=

y

2

+

2

by sketching the sideways parabola  

x

=

y

2

then adding  

2

to the  

x

coordinates (translate  

2

to the right).

Add the  

x

axis and the vertical line  

x

=

4

to the picture:

enter image source here

The area can be found by either

4

2

x

2

/

d

x

or by

2

0

(

4

(

y

2

+

2

)

)

/

d

x

Step-by-step explanation:

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