A particle moving with uniform acceleration has velocity of 6ms- at a distance 5cm from the initial position. After moving another 7m the velocity becomes 8 ms-1 .the initial velocity and acceleration of particle are
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Answer:
v² = u²+2as
36 = u² + 10a
v² = u² + 2as
64 = u² + 24a
36-10a = 64-24a
14a = 28
a = 2m/s²
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