Question

a particle of 0.25kg vibrates with a period of 2sec ,if its greatest displacement is 0.4m, then maximum velocity in m/s​

Answer 1

answer

=0.628s

Explanation:

The force constant of the spring,

k=

x

F

=

0.2

0.5×10

=25N/m

Now, if the mass of 0.25 kg is suspended by the spring, then the period of oscillation,

T=2π

k

m

=2π

25

0.25

=0.628s

Answer 2

Answer:

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Explanation:

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