Question

A particle of charge 1 microcoulomb is at rest in a magnetic field b= -2k tesla.magnetic lorentz force on the charge particle with respect to an observer moving with velocity v= -5i m/s will be​

Answer 1

Answer:

Force on the charge will be $F = 10^{-5} N$

Explanation:

As we know that Lorentz force on charge is reference dependent and here we need to find the force on the charge with respect to a moving reference

As we know that

$F = q(\vec v \times \vec B)$

so here we have

v = velocity of charge with respect to moving observer

so we have

$v = 5 \hat i$

$q = 1 \mu C$

$B = - 2\hat k$

now we have

$F = 10^{-6}(5\hat i \times (-2\hat k))$

$F = 10^{-5} \hat j$

#Learn

Topic : Lorentz force

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Answer 2

Answer:

Science

hope it helps

thanks plz