Question

A particle of charge Q and mass m travels
through a potential difference V from rest. The
final momentum of the particle is:
​

Answer 1

Step-by-step explanation:

given that

charge =Q

mass=m

potential difference=V

the kinetic energy of Q =1/2mv^2-------------------------(i)

also we know that

work = energy

then, potential=work/charge

or work=potential×charge

so W=V×Q

or U=V×Q----------(ii)

then equation (I) &(ii) will be equal

1/2mv^2=QV

mv^2=2QV

multiplying both side by 'm'

(mv)^2=2mQV

mv=√2mQV

hence momentum will be √2mQV