solve the following equation 3(t-3 )=5 (2t-1)
tangiant:
3(t-1)=5(2t-1)
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Answered by
2
3 (t-3)=5 (2t-1)
=3t-9=10t-5
=3t-10t=-5+9
=-7t=4
=t=-4/7
=3t-9=10t-5
=3t-10t=-5+9
=-7t=4
=t=-4/7
Answered by
8
Heya!
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◾Given Equation => 3 ( t - 3 ) = 5 ( 2t - 1 )
=> 3t - 9 = 10t - 5
=> 3t - 10t = -5 + 9
=> -7t = 4
=> t = -4/7
✔Hence the value of t => -4/7
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-----------------------------------------------------------------------------------------------------
◾Given Equation => 3 ( t - 3 ) = 5 ( 2t - 1 )
=> 3t - 9 = 10t - 5
=> 3t - 10t = -5 + 9
=> -7t = 4
=> t = -4/7
✔Hence the value of t => -4/7
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