Write three solutions for the equation 3x + y =12. Also check whether (3, 4) is a solution or not.
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3x + y = 12
3x = 12 - y
x = 12 - y ÷ 3
x = 4 - y
y + x = 4
so we can't assume x and y as 2 and 2 . because when it is 2 then it assume same variable but it is x and y , different variable .
so we can assume 1 and 3 . let see
3x + y = 12
3×3+1=12
3x = 12 - y
x = 12 - y ÷ 3
x = 4 - y
y + x = 4
so we can't assume x and y as 2 and 2 . because when it is 2 then it assume same variable but it is x and y , different variable .
so we can assume 1 and 3 . let see
3x + y = 12
3×3+1=12
sanchitgeorge17:
it is wrong
Answered by
0
Answer:
hii
buddy here is your answer
Step-by-step explanation:
3x + y = 12
3x = 12 - y
x = 12 - y ÷ 3
x = 4 - y
y + x = 4
so we can't assume x and y as 2 and 2 . because when it is 2 then it assume same variable but it is x and y , different variable .
so we can assume 1 and 3 . let see
3x + y = 12
3×3+1=12
(3,4) is not a solution for that equation
since 3(3)+4 is not equal to 12....
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