Question

A particle of charge Q is stationary at a place where the magnetic field is B along the X-axis. The force on the charge due to B is:-

A) proportional to QB along X-direction
B) proportional to Q2(q square) along x direction
C) zero
D) proportional to q under root b in y-z plane

Answer 1

Answer:

Explanation:

I think it is zero because

F=qvbsintheta

As v is 0

F = zero

Answer 2

Answer:

The force on the charge due to B is zero i.e. option(c).

Explanation:

The force on a charge due to the magnetic field is given by,

$F=q(v\times B)$           (1)

Where,

F=force acting on the charged particle

q=value of charge on charge particle

v= velocity with which the charged particle is moving

B=the magnetic field in the region in which the charged particles are moving

We can also write equation (1) as,

$F=qvBsin\theta$           (2)

As per the question,

The charge is stationary so its velocity will be zero and the magnetic field is along the x-axis i.e.Bx

Now from equation (1),

$F=Q(0\times B_x)=0$

Hence, the force on the charge due to B is zero i.e. option(c).