Question

A particle of initial velocity 5m/s after 10 sec it reaches up to 20m/s. Find the distance travel by the particle.



please answer​

Answer 1

u = 5m/s

v =20 m/s

t =10 sec

a = (v-u)/t

=(20-5)/10

=15/10

=1.5m/s^2

We can solve this problem by the Third Equation of Motion

v^2-u^2=2as

(20)^2-(5)^2=2(1.5)(s)

400-25=2(1.5)s

s=(375)/2*1.5

s=125m

Ans. The distance travelled by the object is 125 metres.