Question

A particle of mass 0.3kg is
subjected to a force F=kx with
k=15N/m.What will be its initial acceleration,if it is released from a point 20cm away from the origin?​

Answer 1

Explanation:

use newton's 2 law f= ma and substitute in the equation

Answer 2

Answer :

Acceleration of the particle is - 10 m/s²

Explanation :

Given,

• Mass of the particle (M) = 0.3 Kg

• Spring Constant (K) = 15 N/m

• Displacement (x) = 20cm = 0.2 m

To finD

Initial Acceleration of the particle

We know that,

$\sf F = - Kx$

But F = Ma

$\longrightarrow \sf Ma = - Kx \\ \\ \longrightarrow \sf (0.3)a = - 15 \times 0.2 \\ \\ \longrightarrow \sf a = - \dfrac{15}{3} \times 2 \\ \\ \longrightarrow \sf a = - 5 \times 2 \\ \\ \longrightarrow \boxed{\boxed{\sf a = - 10 ms^{-2}}}$