Question

A particle of mass 0.5 kg travels in a straight line with vel v=ax^3/2 where a=5 m^-1/2 s-1.what is the work done by the net force during its displacement from x=0 to x=2m.

Answer 1

BONJOUR FRIEND ♥
HERE'S THE ANSWER ✌

♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦

#see the attached pic #

⤴⤴⤴⤴⤴⤴⤴

HOPE IT'LL HELP YOU ☺☺☺

Answer 2

$\huge \mathfrak {Answer:-}$

Mass of the body = $0.5\:kg$

Velocity of the body is governed by the equation,

= $ax \frac{3}{2}$and$\:a = 5m \frac{ - 1}{2} s^{ - 1}$

Initial velocity, 

at x = 0 $= 0$

Final velocity,

at x = 2 m$= 10 \sqrt{2} m/s$

Work done = Change in kinetic energy

$=( \frac{ - 1}{2} )m(v^{2} - u ^{2} )$

$= (\frac{ - 1}{2}) \times 0.5[(10 \sqrt{2}) ^{2} - 0 ^{2}]$

$= ( \frac{ - 1}{2} ) \times 0.5 \times 10 \times 10 \times 2$

$= - 50J$

$\huge {Be\:Brainly}$❤️