Question

A particle of mass 0.8 kg is executing shm with an amplitude of 0.1 metre and periodic time 11/7 sec. The velocity and the kinetic energy of the particle at the moment

Answer 1

V = √(A^2 - y^2)

V = 2π/T √(A^2 - y^2)

V = 2×3.14/11/7√[1.0]2 - (0.6)

3.2 msec