Question

Question from ray optics
Question from ray optics A fish is near the centre of a spherical water filled ( = 4/3) fish bowl. A child stands in air at a distance 2R (R is the radius of curvature of the sphere) from the centre ofthe bowl. At what distance from the centre would the child nose appear to the fish situated at the centre :

Answer 1

$(1 \div v) - (4 \div 3u) = - {( - 4 \div 3) + 1} \div r \\ u = 2r \\ (1 \div v) - (2 \div 3r) = (- 1 \div 3)r \\ v = 3r$