Question

A particle of mass 1.6 x 10 to the power-27 kg is revolving in a
circular path of radius 10 cm under the influence of a
centripetal force of 2.5 x 10 to the power -12 N. Find out its angular
velocity.


ans wid exp.​

Answer 1

1.25×10^7

Explanation:

we know centripetal force is equal to mv^2/r

we know the value of centripetal force,mass and radius

so,2.5×10^(-12)=(1.6×10^(-27)×v^2)÷10

here from v is root under 2.5×10^(-12)÷1.6×10^(-28)

it is 1.25×10^8

now we know angular velocity equal to v/r

we have v ,we have r

just do it

1.25×10^7

don't forget unit ......per second

Answer 2

Answer:

hope it will help you.....