Question

A particle of mass 10 gram is executed SHM with an amplitude of 0.5 metre and circular frequency of radial the maximum value of the force acting on the particle during the course of oscillation is​

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Force=0.5N}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Mass (m) = 10g => $\sf{10×10^{-3}kg}$

• Amplitude (A) = 0.5m

• Frequency ($\sf{\omega}$)=10rad/s

$\large\underline\pink{\sf To\:Find: }$

• Force (F) = ?

━━━━━━━━━━━━━━━━━━━━━━━━━━

We know that ,

$\large{\boxed{\sf F=m\omega^2 A}}$

On putting value :

$\large\implies{\sf F=10×10^{-3}×10^2×0.5}$

$\large\implies{\sf F= 0.5N}$

$\huge\red{♡}$$\Large\red{\boxed{\sf Force=0.5N}}$

Hence ,

Force during course of oscillation is 0.5N