Question

A particle of mass 100 g is kept on the surface of a uniform sphere of mass 10 kg and radius 10 cm. Find the work to be done against the gravitational force between them to take the particle away from the sphere.

Answer 1

The work to be performed again the gravitational force is $6.67 \times 10^{-10} \mathrm{J}$. This will take away the particle from the sphere.

Explanation:

• It is to be noted that the work should be performed against the gravity when the object is projected or lifted upward.

• This should be against the gravity's resistance. With constant velocity, when the object moves upwards, the gravity is the force gravity's time of the displacement.
• The particle’s initial potential energy = Work  

         $U i=\frac{G M m}{r}$

        $U i=-6.67 \times 10^{-11} \times 100 \times 10^{-2} 0.1=-6.67 \times 10^{-10} J$

• It is to be understood that work done = Variation in the potential energy

        Therefore,  $W=\Delta U=U f-U i$

       $W=-U i$

       $=6.67 \times 10^{-10} \mathrm{J}$

Answer 2

Answer:

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