Question

A particle of mass 2 kg is moving in a circular
path of radius 1 m with speed v = 21 (where u is
in ms- and t is in 's'). Magnitude of tangential
force acting on the particle is
(1) 2N
(2) 1 N
(3) SN
(4) 4 N​

Answer 1

Answer:

Given mass (m) = 2 kg

Radius (r) = 1m

Speed (v) = 21 m/s

Tangential acceleration(A't) = dv/dt = 0

Force = Mass ×Acceleration =0

So, magnitude of tangential force is 0N

Hope it helps u.