Question

a particle of mass 2 kg is moving in circular path with constant speed 20m/sec the magnitude of change in velocity when particle travels from A to P will be

Answer 1

After completing half revolution :

The particle speed remains constant.

The change in speed will be 0 m/sec.

However there is change in velocity vector.

Both have same magnitude but opposite directions.

So the magnitude of change in velocity will be 20 m/sec

Answer 2

Answer: The magnitude of change in velocity will be $v = 20\sqrt{2}\ m/s$.

Explanation:

Given that,

Mass m = 2 kg

Speed v = 20 m/sec

We taking the components of velocity at A and P

$v_{A}= 20\hat{i}$

$v_{P}=20\hat{j}$

When the particle travels from A to P

The magnitude of change in velocity will be

$v = \sqrt{v_{P}^2+v_{A}^2}$

$v = \sqrt{20^2+20^2}$

$v = 20\sqrt{2}\ m/s$

Hence, The magnitude of change in velocity will be $v = 20\sqrt{2}\ m/s$.