Question

the cost of 10 tables is $ 7500 find the number of table that can be purchased with $9000? Also find the cost of 15 such tables?

Answer 1

Cost of 10 tables = 7500
Cost of 1 table = 750

number of table that can be purchased with $9000
$= \frac{9000}{750} \\ = \frac{1800}{15} \\ = 12$
Cost of 15 tables = 750 × 12 = 9000

Answer 2

Given:

Cost of 10 tables = $ 7500

To Find:

1. Tables that can be purchased with $9000
2. Cost of 15 such tables

Solution:

Tables from $7500 = 10

Thus, table purchased in $1 = 10/7500

Calculating tables that can be purchased from $9000 -

= 10 × 9000/7500

= 900/75

= 12.

Calculating cost of 15 tables -

Cost of one table = 7500/10

= 750

Cost of 15 tables = 750 × 15

= 11250

Answer: From $9000, 12 tables can be purchased. The cost of 15 tables is $ 11,250