Question

A particle of mass 2 kg moves on a circular path with constant speed

Answer 1

according to the question:

the speed remains constant hence the change in speed = 0 m/s

now the change in magnitude of velocity of the particle:

at v₁ = 10 m/s ( intially )

at v₂ = -10 m/s ( as the direction gets reversed )

hence the final answer will be : v₁ - ( - v₂ )= 20 m/s