A particle of mass 2kg is moving in a circular path with constant speed 10m/s. The change in magnitude of velocity, when the particle travels from p to q will be(assume radius of circle is 10/π^2)
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Answer:
The magnitude of the velocity will not change i.e. Δ|v|=0
Explanation:
No external force is acting on the particle, hence it's energy must remain constant
and the velocity will only change it's direction ( hence, a circular path is obtained). The magnitude will remain 10 m/s.
(Assuming circular path in horizontal plane, as not given in the question)
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