Question

a particle of mass 2kg is moving with a velocity of 4m/s attains a velocity of 8m/s in 2 second calculate the amount of force needed to attend this velocity ​

Answer 1

Given Information,

• Mass of the Particle (M) = 2 Kg
• Initial Velocity (u) = 4 m/s
• Final velocity (v) = 8 m/s
• Time (t) = 2 seconds

According to Newton's Second Law,

Rate of change of momentum is properotional to the applied force.

Thus,

$\sf \: F = \dfrac{\Delta{P}}{\Delta{t}} \\ \\ \longrightarrow \sf \: F = \dfrac{mv - mu}{t} \\ \\ \longrightarrow \sf \: F = \dfrac{2 \times 8 - 2 \times 4}{2} \\ \\ \longrightarrow \sf \: F = 8 - 4 \\ \\ \longrightarrow \boxed{ \boxed{\sf \: F \: = 4 \ N}}$

Force required to change the velocity is 4 N

Answer 2

Given,

• Mass of the body = 2kg
• Initial velicity of the body = 4m/s
• Final velocity of the body = 8m/s
• Time taken = 2 seconds

To find,

• The amount of force needed to attend the velocity?

Formula used,

• F = mv - mu/t

Solution,

Let's fine out the amount of force needed to attend the velocity.

F = mv - mu/t

F = 2 × 8 - 2 × 4/2

F = 16 - 8/2

F = 8/2

F = 4N

Therefore, The amount of force needed to attend the velocity is 4 Newton.