Question

A particle of mass 2kg is thrown up with a speed of 19.6 m/s the maximum height attained by the particle is

Answer 1

Answer:

Height=19.6m

Explanation:

I think it is correct answer and I hope you understand it

Answer 2

The maximum height attained by the particle is 19.6 meters.

Explanation:

It is given that,

Mass of the particle, m = 2 kg

It is thrown up with a speed of 19.6 m/s, v = 19.6 m/s

We need to find the maximum height attained by the particle. It can be calculated using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh$

$v=\sqrt{2gh}$

h is the maximum height attained by the particle

$h=\dfrac{v^2}{2g}$

$h=\dfrac{(19.6)^2}{2\times 9.8}$

h = 19.6 m

So, the maximum height attained by the particle is 19.6 meters. Hence, this is the required solution.

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Conservation of energy

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