Question

A particle of mass 2kg moves on a circular path with constant speed 10m/s. find magnitude of change in velocity when pqrticle completes half revolution

Answer 1

Heya.....!!

According to the question, the particle completes Half revolution , So change in velocity I.e ( v₂ - v₁ ) , and v₁ = v₂ as speed is constant. So once the velocity vector will be = v₁ = 10m/s and after the half revolution, magnitude will be same but direction will be opposite i.e = v₂ = 10m/s , Hence :-

Change in velocity → v₂ - v₁

⇒ 10 - ( - 10 )

Answer :- $\huge\boxed{20 m/s}$

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Hope it helps you

Answer 2

according to the question:

the speed remains constant hence the change in speed = 0 m/s

now the change in magnitude of velocity of the particle:

at v₁ = 10 m/s ( intially )

at v₂ = -10 m/s ( as the direction gets reversed )

hence the final answer will be : v₁ - ( - v₂ )= 20 m/s

hope it helps

thanks